A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/12 and the angle between sides B and C is pi/12. If side B has a length of 48, what is the area of the triangle?

1 Answer
Sihan Tawsik
Jan 28, 2016

4299.322531

Explanation:

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lets draw a perpendicular line on B .
suppose, the length of the perpendicular is D
now, the problem says, the angle between A and B is (5pi)/12
now,
in, triangleABD,
D/B=tan((5pi)/12)
or,D=Btan((5pi)/12)
now, by putting the values, B=48 and tan(5pi)/12 ,
D=48*3.732050808
or, D=179.1384388
so,
The area of triangleABC=1/2*B*D
now, by putting the value of B and D in the above equation, we get,
triangleABC=1/2*48*179.1384388=4299.322531

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