A triangle has sides A, B, and C. The angle between sides A and B is (3pi)/4 and the angle between sides B and C is pi/12. If side B has a length of 13, what is the area of the triangle?

1 Answer
Binayaka C.
Apr 21, 2016

Area of the triangle is 30.93 Sq units

Explanation:

The angle between sides B & C is /_A=pi/12=180/12=15^0
The angle between sides A & B is /_C=3*pi/4=3*180/4=135^0
So Angle /_B=180-(135+15)=30^0 Using sine law we get B/sin B=A/sinAor 13/sin30=A/sin15 or A=13*sin15/sin30=6.73 Area = (A.B.sinC)/2 = (13*6.73*sin135)/2=30.93 sq.units

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