A triangle has sides A, B, and C. Sides A and B have lengths of 7 and 5, respectively. The angle between A and C is $(7pi)/24$ and the angle between B and C is $(5pi)/8$ . What is the area of the triangle?

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Answer 1 · 2018-02-17T08:44:41

Since $a/ sin A != b / sin B$ , cannot form a triangle

Given : $a = 7, b = 5, hatA = (5pi)/8, hatB= (7pi)/24$

$hatC = pi - ((5pi)/8 + (7pi)/24) = pi/12$

$a / sin A = 7 / sin ((5pi)/8 = 7.5767$

$b / sin B = 5 / sin ((7pi)/24) = 6.3024$

Since $a/ sin A != b / sin B$ , cannot form a triangle

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A triangle has sides A, B, and C. Sides A and B have lengths of 7 and 5, respectively. The angle between A and C is (7pi)/24(7pi)/24 and the angle between B and C is (5pi)/8 (5pi)/8. What is the area of the triangle?