A triangle has sides A, B, and C. Sides A and B have lengths of 7 and 5, respectively. The angle between A and C is #(7pi)/24# and the angle between B and C is # (5pi)/8#. What is the area of the triangle?

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Answer 1 · 2018-02-17T08:44:41

Since #a/ sin A != b / sin B#, cannot form a triangle

Given : #a = 7, b = 5, hatA = (5pi)/8, hatB= (7pi)/24#

#hatC = pi - ((5pi)/8 + (7pi)/24) = pi/12#

#a / sin A = 7 / sin ((5pi)/8 = 7.5767#

#b / sin B = 5 / sin ((7pi)/24) = 6.3024#

Since #a/ sin A != b / sin B#, cannot form a triangle

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