A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 7, respectively. The angle between A and C is $(17pi)/24$ and the angle between B and C is $(5pi)/24$ . What is the area of the triangle?

Question

1699 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-07T09:47:48

$" Since "color(brown)(a / sin A != b / sin B) , color(indigo)(" we can not form a triangle with the given measurements."$

$hat A = (5pi)/24, a = 6, hat B = (17pi)/24, b = 7$

![https://math.stackexchange.com/questions/811938/law-of-sines-and-cosines]( useruploads.socratic.org )

$a / sin A = b / sin B$

$a / sin A = 6 / sin ((5pi)/24) = 9.86$

$b / sin B = 7 / sin ((7pi)/24) = 8.82$

$" Since "color(brown)(a / sin A != b / sin B) , color(indigo)(" we can not form a triangle with the given measurements."$

A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 7, respectively. The angle between A and C is (17pi)/24(17pi)/24 and the angle between B and C is (5pi)/24 (5pi)/24. What is the area of the triangle?