A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 14, respectively. The angle between A and C is $(17pi)/24$ and the angle between B and C is $(pi)24$ . What is the area of the triangle?

Question

1739 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-04T21:07:57

$1/2*6*14*sin(pi/4)=21root(2)2$

The angle between A and B is given by $theta=pi-17pi/24-pi/24=(24pi-18pi)/24=pi/4$

The area is given by $1/2*A*B*sin(theta)$

A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 14, respectively. The angle between A and C is (17pi)/24(17pi)/24 and the angle between B and C is (pi)24 (pi)24. What is the area of the triangle?