A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 1, respectively. The angle between A and C is $(13pi)/24$ and the angle between B and C is $(3pi)/8$ . What is the area of the triangle?

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Answer 1 · 2016-02-06T12:40:20

$= 2.97" units"^2$ to 2 decimal places

$color(red)(" The question has an error! " )$ Producing the diagram to scale using just the angles shows that it is C that is 1. NOT B.

Tony B

$color(purple)("This gave me a lot of trouble until I drew the diagram near enough to scale!")$

$color(blue)("Assumption: The angles given in relation to the sides is correct.")$

$color(red)("Consequently the length of B is not 1")$

$color(red)("It is the length of C that is 1")$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$"Area "= C/2 Asin((13pi)/24)$

$=1/2xx6xx sin((13pi)/24)$

$= 2.97" units"^2$ to 2 decimal places

A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 1, respectively. The angle between A and C is (13pi)/24(13pi)/24 and the angle between B and C is (3pi)/8 (3pi)/8. What is the area of the triangle?