A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 8, respectively. The angle between A and C is $(pi)/2$ and the angle between B and C is $(pi)/3$ . What is the area of the triangle?

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A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 8, respectively. The angle between A and C is $(pi)/2$ and the angle between B and C is $(pi)/3$ . What is the area of the triangle?

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Answer 1 · 2016-02-12T08:38:28

≈ 15.6

Explanation:

since the angle between A and C is $pi/2$
then triangle ABC is right , with hypotenuse B.

the area is therefore $1/2AC$

To find C , use Pythagoras' Theorem.

$C = sqrt( 8^2 - 5^2) = sqrt(64 - 25) = sqrt39$

hence area = $1/2 xx 5 xx sqrt39 ≈ 15.6$

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A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 8, respectively. The angle between A and C is $(pi)/2$ and the angle between B and C is $(pi)/3$ . What is the area of the triangle?

1 Answer

Explanation:

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A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 8, respectively. The angle between A and C is (pi)/2(pi)/2 and the angle between B and C is (pi)/3 (pi)/3. What is the area of the triangle?

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Explanation:

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A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 8, respectively. The angle between A and C is $(pi)/2$ and the angle between B and C is $(pi)/3$ . What is the area of the triangle?