A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 4, respectively. The angle between A and C is $(5pi)/24$ and the angle between B and C is $(11pi)/24$ . What is the area of the triangle?

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Answer 1 · 2018-02-17T16:21:12

We can not form a triangle.

$hatC = pi - (11pi)/24 - (5pi)/24 = pi/3$

$a/ sin A = 5 / sin ((11pi)/24) = 5.0431$

$b / sin B = 4 / sin ((5pi)/24) = 6.5707$

Since $a / sin A != b / sin B$ , we cannot form a triangle.

A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 4, respectively. The angle between A and C is (5pi)/24(5pi)/24 and the angle between B and C is (11pi)/24 (11pi)/24. What is the area of the triangle?