A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 2, respectively. The angle between A and C is #(3pi)/8# and the angle between B and C is # (5pi)/12#. What is the area of the triangle?

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A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 2, respectively. The angle between A and C is #(3pi)/8# and the angle between B and C is # (5pi)/12#. What is the area of the triangle?

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Answer 1 · 2016-08-02T11:08:10

The area of the triangle is #3.04(2dp)# sq.unit

Explanation:

The angle between sides A and B is #/_c=(pi-((3pi)/8+(5pi)/12))=37.5^0; A=5 ; b=2#.The area of the triangle is #A_t=1/2*A*B*sinc =1/2*5*2*sin37.5=3.04(2dp)#sq.unit[Ans]

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A triangle has sides A, B, and C. Sides A and B have lengths of 5 and 2, respectively. The angle between A and C is #(3pi)/8# and the angle between B and C is # (5pi)/12#. What is the area of the triangle?

1 Answer

Explanation:

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