A triangle has sides A, B, and C. Sides A and B have lengths of 4 and 5, respectively. The angle between A and C is $(pi)/8$ and the angle between B and C is $(pi)/12$ . What is the area of the triangle?

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Answer 1 · 2018-03-27T11:47:03

$color(maroon)(A_t = (1/2) a b sin C = 6.09 " sq units"$

$hat A = pi/12, hat B = pi/8, a = 4, b = 5$

To find the area of the triangle $A_t$

$hat C = pi - pi/12 - pi/8 = (19pi)/24$

$A_t = (1/2) a b sin C = (1/2) * 4 * 5 * sin ((19pi)/24)$

$=> 6.09 " sq units"$

A triangle has sides A, B, and C. Sides A and B have lengths of 4 and 5, respectively. The angle between A and C is (pi)/8(pi)/8 and the angle between B and C is (pi)/12 (pi)/12. What is the area of the triangle?