A triangle has sides A, B, and C. Sides A and B have lengths of 3 and 4, respectively. The angle between A and C is $(5pi)/24$ and the angle between B and C is $(pi)/8$ . What is the area of the triangle?

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Answer 1 · 2017-11-05T11:29:19

Area of the triangle is $3sqrt3$ sq.unit.

Angle between Sides $A and C$ is $/_b= (5pi)/24$

$=(5*180)/24=37.5^0$

Angle between Sides $B and C$ is $/_a= pi/8=180/8=22.5^0 :.$

Angle between Sides $A and B$ is

$/_c= 180-(37.5+22.5)=120^0$

We know sides $A=3 , B=4$ and their included angle $/_c=120^0$

Area of the triangle is $A_t=(A*B*sinc)/2= (3*4*sin120)/2$

$= 6 sin120 =6 *sqrt3/2 =3sqrt3$ sq.unit

A triangle has sides A, B, and C. Sides A and B have lengths of 3 and 4, respectively. The angle between A and C is (5pi)/24(5pi)/24 and the angle between B and C is (pi)/8 (pi)/8. What is the area of the triangle?