A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 4, respectively. The angle between A and C is $(13pi)/24$ and the angle between B and C is $(5pi)/24$ . What is the area of the triangle?

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Answer 1 · 2016-01-06T18:31:28

$2sqrt2$

Sides a, b are given and the angle between these two would be $2pi -( (13pi)/24 + (5pi)/24)$ = $(5pi)/4$

Area would be $1/2 ab sin((5pi)/4)$ = $1/2 (2)(4)(sqrt2) /2$ = $2sqrt2$

A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 4, respectively. The angle between A and C is (13pi)/24(13pi)/24 and the angle between B and C is (5pi)/24 (5pi)/24. What is the area of the triangle?