A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is $\frac{7 π}{24}$ $(7pi)/24$ and the angle between B and C is $\frac{13 π}{24}$ $(13pi)/24$ . What is the area of the triangle?

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Answer 1 · 2017-06-22T13:49:00

The area of the triangle is $= 1.5 u^{2}$ $=1.5u^2$

The angle between $A$ $A$ and $B$ $B$ is

$= π - (\frac{7}{24} π + \frac{13}{24} π)$ $=pi-(7/24pi+13/24pi)$

$= π - (\frac{20}{24} π)$ $=pi-(20/24pi)$

$= \frac{1}{6} π$ $=1/6pi$

The side $A$ $A$ is $= 2$ $=2$

The side $B$ $B$ is $= 3$ $=3$

$sin (\frac{1}{6} π) = \frac{1}{2}$ $sin(1/6pi)=1/2$

The area of the triangle is

$A = \frac{1}{2} \cdot 2 \cdot 3 sin (\frac{1}{6} π)$ $A=1/2*2*3sin(1/6pi)$

$= 1.5$ $=1.5$

A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is (7pi)/247π24(7pi)/24 and the angle between B and C is (13pi)/2413π24 (13pi)/24. What is the area of the triangle?