A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is #(11pi)/24# and the angle between B and C is # (7pi)/24#. What is the area of the triangle?

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Answer 1 · 2017-01-18T02:35:15

Area = (½) * 3 * 2.12 = 3.18

Triangle area = (1/2)(base)(height)

Take side B to be the base, then h is the sin of the angle between sides B and A times the length of B.

That angle is (π - 7π/24 – 11π/24) = 6π/24

sin C = h/B ; sin (6π/24) = h/3

h = sin(0.785) * 3 ; h = 0.707 * 3 = 2.12

Area = (½) * 3 * 2.12= 3.18