A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is $(5pi)/24$ and the angle between B and C is $(3pi)/8$ . What is the area of the triangle?

Question

1571 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-20T04:34:13

$2.9squnit$

Given

$A,B,C " are three sides of a triangle"$

$A=2 and B =3$

$"Angle between A & C"=((5pi)/24)$

$"Angle between B & C"=((3pi)/8)$

$"Let Angle between A & B"=theta$
$=pi-(3pi)/8-(5pi)/24=((24-9-5)pi)/24=(5pi)/12$

$"Area of triangle"=1/2*A*B*sintheta$

$=1/2*2*3*sin((5pi)/12)=2.9squnit$

A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is (5pi)/24(5pi)/24 and the angle between B and C is (3pi)/8 (3pi)/8. What is the area of the triangle?