A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 12, respectively. The angle between A and C is $(13pi)/24$ and the angle between B and C is $(5pi)/24$ . What is the area of the triangle?

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Answer 1 · 2018-05-17T05:38:59

We can not form a triangle with the given measurements

$a = 2,b = 12, hat A = (5pi)/24, hat B = (13pi)/24$

As per Law of Sines, $a / sin a = b / sin B$

$a / sin A = 2 / sin ((5pi)/24) = 3.29$

$b / sin B -= 12 / sin ((13pi)/24) = 12.1$

Since values don’t satisfy the sine law, we can not form a triangle with the given measurements

A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 12, respectively. The angle between A and C is (13pi)/24(13pi)/24 and the angle between B and C is (5pi)/24 (5pi)/24. What is the area of the triangle?