A triangle has sides A, B, and C. Sides A and B have lengths of 12 and 14, respectively. The angle between A and C is $\frac{13 π}{24}$ $(13pi)/24$ and the angle between B and C is $\frac{3 π}{8}$ $(3pi)/8$ . What is the area of the triangle?

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Answer 1 · 2017-07-01T09:15:06

The area of the triangle is $= 21.74 u^{2}$ $=21.74u^2$

The angle between $A$ $A$ and $B$ $B$ is

$= π - (\frac{13}{24} π + \frac{3}{8} π)$ $=pi-(13/24pi+3/8pi)$

$= π - \frac{22}{24} π = \frac{2}{24} π = \frac{1}{12} π$ $=pi-22/24pi=2/24pi=1/12pi$

The area of the triangle is

$= \frac{1}{2} A B sin (\frac{1}{12} π)$ $=1/2AB sin(1/12pi)$

$= \frac{1}{2} \cdot 12 \cdot 14 \cdot sin (\frac{1}{12} π)$ $=1/2*12*14*sin(1/12pi)$

$= 21.74$ $=21.74$

A triangle has sides A, B, and C. Sides A and B have lengths of 12 and 14, respectively. The angle between A and C is 13π24(13pi)/24 and the angle between B and C is 3π8 (3pi)/8. What is the area of the triangle?