A triangle has sides A, B, and C. Sides A and B have lengths of 10 and 4, respectively. The angle between A and C is $(7pi)/24$ and the angle between B and C is $(pi)/8$ . What is the area of the triangle?

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Answer 1 · 2018-05-14T09:28:10

$A=19.31851653 cm^2$

$[7pi]/24+pi/8=[7pi]/24+[3pi]/24=[10pi]/24$

The angle at C is $[24pi]/24-[10pi]/24=[14pi]/24$

Area of the triangle is $1/2 xxaxxbxxsinC$

A= $1/2 xx 10 xx 4 xx sin [[14pi]/24]$

A=19.31851653

A triangle has sides A, B, and C. Sides A and B have lengths of 10 and 4, respectively. The angle between A and C is (7pi)/24(7pi)/24 and the angle between B and C is (pi)/8 (pi)/8. What is the area of the triangle?