A triangle has sides A, B, and C. Sides A and B are of lengths $7$ and $12$ , respectively, and the angle between A and B is $(7pi)/12$ . What is the length of side C?

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A triangle has sides A, B, and C. Sides A and B are of lengths $7$ and $12$ , respectively, and the angle between A and B is $(7pi)/12$ . What is the length of side C?

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Answer 1 · 2016-08-09T21:02:45

$C=15.4$

Explanation:

As per law of cosines
$C^2=A^2+B^2-2Atimes Btimescos(theta)$ where $A=7;B=12 and theta=(7pi)/12$
or
$C^2=7^2+12^2-2times7times12timescos((7pi)/12)$
or
$C^2=49+144-168times(-0.2588)$
or
$C^2=49+144+43.48$
or
$C^2=236.4.8$
or
$C=sqrt236.48$
or
$C=15.4$

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A triangle has sides A, B, and C. Sides A and B are of lengths $7$ and $12$ , respectively, and the angle between A and B is $(7pi)/12$ . What is the length of side C?

1 Answer

Explanation:

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A triangle has sides A, B, and C. Sides A and B are of lengths $7$ and $12$ , respectively, and the angle between A and B is $(7pi)/12$ . What is the length of side C?