A triangle has sides A, B, and C. Sides A and B are of lengths 5 and 3, respectively, and the angle between A and B is (3pi)/4 . What is the length of side C?

1 Answer
Aug 12, 2016

C=7.43

Explanation:

As per law of cosines
C^2=A^2+B^2-2Atimes Btimescos(theta) where A=5;B=3 and theta=(3pi)/4
or
C^2=5^2+3^2-2times5times3timescos((3pi)/4)
or
C^2=25+9-30times(-0.707)
or
C^2=34+21.21
or
C^2=55.21
or
C=sqrt55.21
or
C=7.43