A triangle has sides A, B, and C. Sides A and B are of lengths #2# and #4#, respectively, and the angle between A and B is #(11pi)/12 #. What is the length of side C?

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Answer 1 · 2016-02-15T08:52:29

Side #c=5.95439" " "#units

The given are 2 sides and an included angle. So, use Law of Cosines for sides

Given #a=2# and #b=4# and #C=(11pi)/12#

#c=sqrt(a^2+b^2-2*a*b*cos C)#

#c=sqrt(2^2+4^2-2*2*4*cos ((11pi)/12)#

#c=sqrt(4+16-16*cos ((11pi)/12)#

#c=sqrt(35.45481322)#

#c=5.95439#

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