A triangle has sides A, B, and C. Sides A and B are of lengths 1414 and 1212, respectively, and the angle between A and B is (5pi)/8 5π8. What is the length of side C?
1 Answer
Mar 10, 2016
≈ 21.647 units
Explanation:
Given a triangle with 2 sides and the angle between them known, find the 3rd side using the
color(blue)" cosine rule " cosine rule
c^2 = a^2 + b^2 - (2ab costheta)c2=a2+b2−(2abcosθ) where c is the side to be found , a and b are the known sides and
theta " is the angle between them "θ is the angle between them here a = 14 , b = 12 and
theta = (5pi)/8θ=5π8 hence
c^2 = 14^2 + 12^2 -( 2xx14xx12 cos((5pi)/8))c2=142+122−(2×14×12cos(5π8))
= 196+144 + 128.582... ≈ 468.582
rArr c = sqrt468.582 ≈ 21.647 " units "