A triangle has sides A, B, and C. Sides A and B are of lengths $10$ and $12$ , respectively, and the angle between A and B is $(7pi)/12$ . What is the length of side C?

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Answer 1 · 2016-05-03T11:12:09

c= 13.4846

The question to be solved is as shown in the figure enter image source here

Now using cosine formula side $c^2= 100+144-2(10)(12)cos (7pi)/12$

$c^2 = 244 -240 cos 105^o$

    = 244-240(-0.2588)  =181.88

c=13.4846

A triangle has sides A, B, and C. Sides A and B are of lengths 1010 and 1212, respectively, and the angle between A and B is (7pi)/12 (7pi)/12 . What is the length of side C?