A triangle has sides A, B, and C. If the angle between sides A and B is $(pi)/8$ , the angle between sides B and C is $(7pi)/12$ , and the length of B is 12, what is the area of the triangle?

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Answer 1 · 2018-02-17T16:12:30

Area of triangle

$A_t = (1/2) a b sin C = 33.5467$

$hatA = (7pi)/12, hatC = (pi)/8, b = 12$

$hatB = pi - (7pi)/12 - pi/8 = (7pi)/24$

$a = (12 * sin ((7pi)/12)) / sin((7pi)/24) = 14.6103$

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Area of triangle

$A_t = (1/2) a b sin C = (1/2) * 14.6103 * 12 * sin (pi/8) = 33.5467$

A triangle has sides A, B, and C. If the angle between sides A and B is (pi)/8(pi)/8, the angle between sides B and C is (7pi)/12(7pi)/12, and the length of B is 12, what is the area of the triangle?