A triangle has sides A,B, and C. If the angle between sides A and B is #(pi)/8#, the angle between sides B and C is #pi/4#, and the length of B is 1, what is the area of the triangle?

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A triangle has sides A,B, and C. If the angle between sides A and B is #(pi)/8#, the angle between sides B and C is #pi/4#, and the length of B is 1, what is the area of the triangle?

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Answer 1 · 2016-02-23T07:02:01

(#sqrt#2 #-# 1) / (2#sqrt#2).

Explanation:

Angle between B and C is 5#pi#/8 .
Use sides are proportional to sines of opposite angles and area to find C = tan #pi#/8.
Area = 1/2 B.C. sin #pi#4.= sin#pi#/8 .sin#pi#/8 = ( 1 #-# cos #pi#/4)/2

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A triangle has sides A,B, and C. If the angle between sides A and B is #(pi)/8#, the angle between sides B and C is #pi/4#, and the length of B is 1, what is the area of the triangle?

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Explanation:

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