A triangle has sides A, B, and C. If the angle between sides A and B is (pi)/3, the angle between sides B and C is (7pi)/12, and the length of B is 7, what is the area of the triangle?

1 Answer
Deepak G.
Aug 7, 2016

=79.16

Explanation:

This is a triangle where side B=7 is opposite of the
Angle [pi-(pi/3+7pi/12)]=pi-11pi/12=pi/12
Therefore
B/sin(pi/12)=C/sin(pi/3)
or
7/sin(pi/12)=C/sin(pi/3)
or
C=7sin(pi/3)/(sinpi/12)
or
C=7(3.34)
or
C=23.42
Height of the triangle is =7sin(pi-7pi/12)=7sin (5pi/12)=6.76
Therefore
Area of the triangle=1/2(C)(Height)
=1/2(23.42)(6.76)
=79.16

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