A triangle has sides A, B, and C. If the angle between sides A and B is $(pi)/3$ , the angle between sides B and C is $pi/3$ , and the length of B is 17, what is the area of the triangle?

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Answer 1 · 2016-03-07T08:19:47

Area $=sqrt3/4*17^2=(289sqrt3)/4=125.141" "$ square units

The triangle is an equiangular triangle with all angles $=pi/3=60^@$

Formula for the area $=sqrt3/4*s^2$

with side $s=17$

we compute the Area $=sqrt3/4*17^2=(289sqrt3)/4=125.141" "$ square units

God bless.... I hope the explanation is useful.

A triangle has sides A, B, and C. If the angle between sides A and B is (pi)/3(pi)/3, the angle between sides B and C is pi/3pi/3, and the length of B is 17, what is the area of the triangle?