A triangle has sides A,B, and C. If the angle between sides A and B is $\frac{π}{2}$ $(pi)/2$ , the angle between sides B and C is $\frac{π}{4}$ $pi/4$ , and the length of B is 4, what is the area of the triangle?

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A triangle has sides A,B, and C. If the angle between sides A and B is $\frac{π}{2}$ $(pi)/2$ , the angle between sides B and C is $\frac{π}{4}$ $pi/4$ , and the length of B is 4, what is the area of the triangle?

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Answer 1 · 2016-02-20T20:13:50

area = 8 square units

Explanation:

Since the angle between A and B is $\frac{π}{2} then this is a right triangle with side C , the hypotenuse$ $pi/2 " then this is a right triangle with side C , the hypotenuse"$

Further , since the angle between B and C is $\frac{π}{4}$ $pi/4$

Then the angle between A and C must be $\frac{π}{4}$ $pi/4$

Making this a right isosceles triangle. Hence B = 4 then A = 4

and Area = $\frac{1}{2} \times B \times A = \frac{1}{2} \times 4 \times 4 = 8 square units$ $1/2 xx B xxA = 1/2 xx 4 xx 4 = 8 " square units"$

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A triangle has sides A,B, and C. If the angle between sides A and B is $\frac{π}{2}$ $(pi)/2$ , the angle between sides B and C is $\frac{π}{4}$ $pi/4$ , and the length of B is 4, what is the area of the triangle?

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A triangle has sides A,B, and C. If the angle between sides A and B is π2(pi)/2, the angle between sides B and C is π4pi/4, and the length of B is 4, what is the area of the triangle?

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A triangle has sides A,B, and C. If the angle between sides A and B is $\frac{π}{2}$ $(pi)/2$ , the angle between sides B and C is $\frac{π}{4}$ $pi/4$ , and the length of B is 4, what is the area of the triangle?