A triangle has sides A, B, and C. If the angle between sides A and B is (5pi)/12, the angle between sides B and C is (5pi)/12, and the length of B is 6, what is the area of the triangle?

1 Answer
Deepak G.
Aug 4, 2016

=33.62

Explanation:

Since the triangle is isosceles height divides the base equally.
In other words the said triangle consists of 2 right angled triangles with base=B/2=6/2=3 and hypotenuse =Side A
Therefore we can write
A(cos((5pi)/12))=3
or
A(0.2588)=3
or
A=3/0.2588
or
A=11.6
In a right angled triangle height h=sqrt(11.6^2-3^2)=11.21
Therefore Area of the triangle=1/2(h)(B)
=1/2(11.21)(6)
=(11.21)(3)
=33.62

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