A triangle has sides A,B, and C. If the angle between sides A and B is $(2pi)/3$ , the angle between sides B and C is $pi/4$ , and the length of B is 13, what is the area of the triangle?

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A triangle has sides A,B, and C. If the angle between sides A and B is $(2pi)/3$ , the angle between sides B and C is $pi/4$ , and the length of B is 13, what is the area of the triangle?

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Answer 1 · 2016-02-16T03:42:58

(169 $sqrt$ 6 / 8) cosec ( $pi/12$ ) = 200, areal units, nearly

Explanation:

Using lower case letters a, b and c for angles and a + b + c = $pi$ ,
.with a = $pi/4$ and c = $2pi/3$ , b = $pi/12$ .
Using B/sin(b) = A/sin(a), A = 13 sin( $pi/4$ ) / sin ( $pi/12$ )
Using, area = base X altitude / 2, the answer is B X A X sin (c) / 2.

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A triangle has sides A,B, and C. If the angle between sides A and B is $(2pi)/3$ , the angle between sides B and C is $pi/4$ , and the length of B is 13, what is the area of the triangle?

1 Answer

Explanation:

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A triangle has sides A,B, and C. If the angle between sides A and B is (2pi)/3(2pi)/3, the angle between sides B and C is pi/4pi/4, and the length of B is 13, what is the area of the triangle?

1 Answer

Explanation:

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A triangle has sides A,B, and C. If the angle between sides A and B is $(2pi)/3$ , the angle between sides B and C is $pi/4$ , and the length of B is 13, what is the area of the triangle?