A triangle has corners at (9 ,4 ), (7 ,1 ), and (3 ,6 ). What is the area of the triangle's circumscribed circle?

1 Answer
Jun 13, 2017

The area of the circumscribed circle is =34.6u^2

Explanation:

To calculate the area of the circle, we must calculate the radius r of the circle

Let the center of the circle be O=(a,b)

Then,

(9-a)^2+(4-b)^2=r^2.......(1)

(7-a)^2+(1-b)^2=r^2..........(2)

(3-a)^2+(6-b)^2=r^2.........(3)

We have 3 equations with 3 unknowns

From (1) and (2), we get

81-18a+a^2+16-8b+b^2=49-14a+a^2+1-2b+b^2

4a+6b=47

4a+6b=47.............(4)

From (2) and (3), we get

49-14a+a^2+1-2b+b^2=9-6a+a^2+36-12b+b^2

8a-10b=5

8a-10b=5..............(5)

From equations (4) and (5), we get

94-12b=5+10b

22b=89

b=89/22

4a=47-6*89/22=47-3*89/11=250/11, =>, a=250/44=125/22

The center of the circle is =(125/22,89/22)

r^2=(3-125/22)^2+(6-89/22)^2=(59/22)^2+(43/22)^2

=5330/484

=2665/242

The area of the circle is

A=pi*r^2=2665/242*pi=34.6