A triangle has corners at (8 ,7 ), (2 ,1 ), and (5 ,6 ). What is the area of the triangle's circumscribed circle?

1 Answer
Jul 12, 2017

The area of the circle is =133.5u^2

Explanation:

To calculate the area of the circle, we must calculate the radius r of the circle

Let the center of the circle be O=(a,b)

Then,

(8-a)^2+(7-b)^2=r^2.......(1)

(2-a)^2+(1-b)^2=r^2..........(2)

(5-a)^2+(6-b)^2=r^2.........(3)

We have 3 equations with 3 unknowns

From (1) and (2), we get

64-16a+a^2+49-14b+b^2=4-4a+a^2+1-2b+b^2

12a+12b=108

a+b=9.............(4)

From (2) and (3), we get

4-4a+a^2+1-2b+b^2=25-10a+a^2+36-12b+b^2

6a+10b=56

3a+5b=28..............(5)

From equations (4) and (5), we get

3(9-b)+5b=28

27-3b+5b=28

2b=1, =>, b=1/2

a=9-1/2, =>, a=17/2

The center of the circle is =(17/2,1/2)

r^2=(2-17/2)^2+(1-1/2)^2=(-13/2)^2+(1/2)^2

=170/4

=85/2

The area of the circle is

A=pi*r^2=pi*85/2=133.5