A triangle has corners at (5 ,3 ), (2 ,4 ), and (7 ,2 ). What is the area of the triangle's circumscribed circle?

1 Answer
Binayaka C.
Jul 13, 2016

Area of circumscribed circle is 1502.48(2dp) sq unit

Explanation:

Side A=sqrt((5-2)^2+(3-4)^2) = sqrt10=3.16
Side B=sqrt((2-7)^2+(4-2)^2) = sqrt29=5.39
Side B=sqrt((7-5)^2+(2-3)^2) = sqrt5=2.24
Semi perimeter s=(3.16+5.39+2.24)/2 =5.395
Area A_r=sqrt(5.395(5.395-3.16)(5.395-5.39)(5.395-2.24))=0.436
Radius of circumscribed circle is (A*B*C)/(4*A_r) =(3.16*5.39*2.24)/(4*0.436) =21.869
Area of circumscribed circle is pi*21.869^2=1502.48(2dp)sq unit[Ans]

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