A triangle has corners at (5 ,2 )(5,2), (8 ,1 )(8,1), and (3 ,4 )(3,4). What is the area of the triangle's circumscribed circle?

1 Answer
Dec 7, 2016

"area is 42.5"piarea is 42.5π

Explanation:

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"the points A,B,C are on the circle."the points A,B,C are on the circle.
"we can write the fallowing equations"we can write the fallowing equations

A(5,2)A(5,2)

x^2+y^2+ax+bx+c=0x2+y2+ax+bx+c=0
5^2+2^2+5a+2b+c=052+22+5a+2b+c=0
25+4+5a+2b+c=025+4+5a+2b+c=0

5a+2b+c=-29" (1)"5a+2b+c=29 (1)

B(8,1)B(8,1)

x^2+y^2+ax+bx+c=0x2+y2+ax+bx+c=0
8^2+1^2+8a+b+c=082+12+8a+b+c=0
64+1+8a+b+c=064+1+8a+b+c=0

8a+b+c=-65" (2)"8a+b+c=65 (2)

C(3,4)C(3,4)

x^2+y^2+ax+bx+c=0x2+y2+ax+bx+c=0
3^2+4^2+3a+4b+c=032+42+3a+4b+c=0
9+16+3a+4b+c=09+16+3a+4b+c=0

3a+4b+c=-25" (3)"3a+4b+c=25 (3)

"let's add the equation (2) to (3)"let's add the equation (2) to (3)
11a+5b+2c=-90" (4)"11a+5b+2c=90 (4)

"expand the equation (1) by 2"expand the equation (1) by 2
10a+4b+2c=-58" (5)"10a+4b+2c=58 (5)

"subtract the equation (5) from (4)"subtract the equation (5) from (4)

a+b=-32" (5)"a+b=32 (5)

"subtract the equation (1) from (2)"subtract the equation (1) from (2)

3a-b=-36" (6)"3ab=36 (6)

"now add (5) to (6)"now add (5) to (6)

4a=-684a=68

color(red)(a=-17)a=17

"use (5)"use (5)

-17+b=-3217+b=32

b=-32+17b=32+17

color(red)(b=-15)b=15

"use (2)"use (2)

8(-17)-15+c=-658(17)15+c=65

-136-15+c=-6513615+c=65

c=-65+151c=65+151

color(red)(c=86)c=86

"r:radius of circle"r:radius of circle

r=sqrt(a^2+b^2-4c)/2r=a2+b24c2

r=sqrt(289+225-344)/2r=289+2253442

r=sqrt(514-344)r=514344

r=sqrt(170)/2r=1702

r^2=170/4=42.5r2=1704=42.5

area=pi*r^2area=πr2

area=42.5piarea=42.5π