A triangle has corners at #(-3 ,-1 )#, #(5 ,6 )#, and #(-4 ,7 )#. If the triangle is dilated by a factor of #1/3 # about point #(2 ,-1 ), how far will its centroid move?

1 Answer
Jul 14, 2018

#color(green)("Distance moved by centroid " color(crimson)(vec(GG') ~~ 4.4721 " units"#

Explanation:

#A(-3,-1), B(5,6), C(-4, 7), " about point " D (2,-1), " dilation factor "1/3#

Centroid #G(x,y) = ((x_a + x_b + x_c) /3, (y_a + y_b + y_c)/3)#

#G(x,y) = ((-3+5 - 4)/3, (-1 + 6 + 7)/3) = (-2/3, 4)#

#A'((x),(y)) = 1/3a - -2/3d = 1/3*((-3),(-1)) - -2/3*((2),(-1)) = ((1/3),(-1))#

#B'((x),(y)) = 1/3b - -2/3d = 1/3*((5),(6)) - -2/3*(2),(-1)) = ((3),4/3))#

#C'((x),(y)) = 1/3c - -2/3d = 1/3*((-4),(7)) - -2/3*((2),(-1)) = ((0),(5/3))#

#"New Centroid " G'(x,y) = ((1/3+ 3 + 0)/3,(-1+ 4/3 + 5/3)/3) = (10/3,2)#

#color(green)("Distance moved by centroid " #

#color(crimson)(vec(GG') = sqrt((-2/3- 10/3)^2 + (4 - 2)) ~~ 4.4721 " units"#