A triangle has corners at $(3, 1)$ $(3, 1 )$ , $(2, 3)$ $( 2, 3 )$ , and $(2, 6)$ $( 2 , 6 )$ . If the triangle is dilated by $\frac{1}{5} x$ $1/5 x$ around $(1, 1)$ $(1, 1)$ , what will the new coordinates of its corners be?

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A triangle has corners at $(3, 1)$ $(3, 1 )$ , $(2, 3)$ $( 2, 3 )$ , and $(2, 6)$ $( 2 , 6 )$ . If the triangle is dilated by $\frac{1}{5} x$ $1/5 x$ around $(1, 1)$ $(1, 1)$ , what will the new coordinates of its corners be?

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Answer 1 · 2018-07-14T02:38:21

$New coordinates are (\frac{7}{5}, 1), (\frac{6}{5}, \frac{7}{5}), (\frac{6}{5}, 2)$ $color(indigo)("New coordinates are " (7/5,1), (6/5,7/5), (6/5,2)$

Explanation:

$A (3, 1), B (2, 3), C (2, 6), about point D (1, 1), dilation factor \frac{1}{5}$ $A(3,1), B(2,3), C(2,6), " about point " D (1,1), " dilation factor "1/5$

$A'((x),(y)) =(1/5)a - (-4/5)d =(1/5)*((3),(1)) - (-4/5)*((1),(1)) = ((7/5),(1))$

$B'((x),(y)) = (1/5)b - (-4/5)d = (1/5)*((2),(3)) - (-4/5)*((1),(1)) = ((6/5),(7/5))$

$C'((x),(y)) = (1/5)c - (-4/5)d = (1/5)*((2),(6)) - (-4/5)*((1),(1)) = ((6/5),(2))$

$color(indigo)("New coordinates are " (7/5,1), (6/5,7/5), (6/5,2)$

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A triangle has corners at $(3, 1)$ $(3, 1 )$ , $(2, 3)$ $( 2, 3 )$ , and $(2, 6)$ $( 2 , 6 )$ . If the triangle is dilated by $\frac{1}{5} x$ $1/5 x$ around $(1, 1)$ $(1, 1)$ , what will the new coordinates of its corners be?

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Explanation:

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A triangle has corners at (3, 1 )(3,1)(3, 1 ), ( 2, 3 )(2,3)( 2, 3 ), and ( 2 , 6 )(2,6)( 2 , 6 ). If the triangle is dilated by 1/5 x15x 1/5 x around (1, 1)(1,1)(1, 1), what will the new coordinates of its corners be?

1 Answer

Explanation:

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A triangle has corners at $(3, 1)$ $(3, 1 )$ , $(2, 3)$ $( 2, 3 )$ , and $(2, 6)$ $( 2 , 6 )$ . If the triangle is dilated by $\frac{1}{5} x$ $1/5 x$ around $(1, 1)$ $(1, 1)$ , what will the new coordinates of its corners be?