"The original triangle and its centroid is shown in figure below."
"the original centroid can be calculated using:"
x=(-2+3+5)/3=6/3=2
y=(3+2+-6)/3=-1/3=-0,33
E(2,-0.33)
"Now dilate A(-2,3) by factor 2 with respect to D(1,-8)"
A(-2,3) rArr A'(1-3*2,3+11*2)
A'(1-3*2,-8+11*2)
A'(-5,14)" (shown in figure below)"
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"Dilate B(3,2) by factor 2 with respect to D(1,-8)"
![enter image source here]()
B(3,2) rArr B'(1+2*2,-8+10*2)
B'(1+2*2,-8+10*2)
B'(5,12)" (shown in figure below)"
"Dilate C(5,-6) by factor 2 with respect to D(1,-8)"
C(5,-6) rArr C'(1+4*2,-8+2*2)
C'(1+4*2,-8+2*2)
C'(9,-4)" (shown figure below)"
"Finally.."
"the dilated centroid can be calculated "
x'=(-5+5+9)/3=9/3=3
y'=(14+12-4)/3
y'=22/3=7,33
F(3,7.33)
"distance between E and F"
d=sqrt((3-2)^2+(7.33+0.33)^2)
d=sqrt(1+(7.66)^2)
d=sqrt(1+58.68)
d=sqrt(59.68)
d=7.73