A triangle has corners at (1, 2 ), ( 2, 3 ), and ( 1 , 5 ). If the triangle is dilated by 4 x around (3, 1), what will the new coordinates of its corners be?

2 Answers
Jun 9, 2017

The new coordinates are (-5,5), (-1,9) and (-5,17)

Explanation:

Let the corners of the triangle be

A=(1,2)

B=(2,3)

C=(1,5)

And the point D=(3,1)

Let the corners of the triangle be

A'=(x,y), B'=(x',y') and C'=(x'',y'') after dilatation.

vec(DA')=4vec(DA)

((x-3),(y-1))=4((1-3),(2-1))=((-8),(4))

x-3=-8, =>, x=-5

y-1=4, =>, y=5

So,

A'=(-5,5)

vec(DB')=4vec(DB)

((x'-3),(y'-1))=4((2-3),(3-1))=((-4),(8))

x'-3=-4, =>, x'=-1

y'-1=8, =>, y'=9

B'=(-1,9)

vec(DC')=4vec(DC)

((x''-3),(y''-1))=4((1-3),(5-1))=((-8),(16))

x''-3=-8, =>, x''=-5

y''-1=16, =>, y''=17

C'=(-5,17)

Jun 9, 2017

(-5,5),(-1,9),(-5,17)

Explanation:

"let the vertices of the triangle be"

A(1,2),B(2,3)" and " C(1,5)

"and A',B',C' be the images of A,B and C respectively"
"under the dilatation"

"let the centre of dilatation be "D(color(magenta)(3),color(blue)(1))

• vec(DA)=ula-uld=((1),(2))-((3),(1))=((-2),(1))

rArrvec(DA')=color(red)(4)vec(DA)=color(red)(4)((-2),(1))=((-8),(4))

rArrA'=(color(magenta)(3)-8,color(blue)(1)+4)=(-5,5)

• vec(DB)=ulb-uld=((2),(3))-((3),(1))=((-1),(2))

rArrvec(DB')=color(red)(4)vec(DB)=color(red)(4)((-1),(2))=((-4),(8))

rArrB'=(color(magenta)(3)-4,color(blue)(1)+8)=(-1,9)

• vec(DC)=ulc-uld=((1),(5))-((3),(1))=((-2),(4))

rArrvec(DC')=color(red)(4)vec(DC)=color(red)(4)((-2),(4))=((-8),(16))

rArrC'=(color(magenta)(3)-8,color(blue)(1)+16))=(-5,17)