A tank contains helium gas at 490 mmHg, nitrogen 0.75 atm, and neon at 520 torr. What is the total pressure in atm?

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A tank contains helium gas at 490 mmHg, nitrogen 0.75 atm, and neon at 520 torr. What is the total pressure in atm?

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Answer 1 · 2016-12-09T05:45:10

Well, we turn the measurements of pressure into $atmospheres$ $"atmospheres"$ , and get...........

Explanation:

$P_{He} + P_{N_{2}} + P_{Ne} =$ $P_"He"+P_(N_2)+P_"Ne"=$

$\frac{490 \cdot m m \cdot H g}{760 \cdot m m \cdot H g \cdot a t m^{- 1}} + 0.75 \cdot a t m + \frac{520 \cdot m m \cdot H g}{760 \cdot m m \cdot H g \cdot a t m^{- 1}} ≅ 2 \cdot a t m .$ $(490*mm*Hg)/(760*mm*Hg*atm^-1)+0.75*atm+(520*mm*Hg)/(760*mm*Hg*atm^-1)~=2*atm.$

You know that $1 \cdot a t m \equiv 760 \cdot m m \cdot H g$ $1*atm-=760*mm*Hg$ . Or rather that one atmosphere will support a column of mercury $760 \cdot m m$ $760*mm$ high. You must simply know this. This measurement of pressure should not really be used above $1 \cdot a t m$ $1*atm$ .

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A tank contains helium gas at 490 mmHg, nitrogen 0.75 atm, and neon at 520 torr. What is the total pressure in atm?

1 Answer

Explanation:

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