A standard pair of six sided dice is rolled. What is the probability of rolling a sum less than or equal to 10?

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Answer 1 · 2017-02-08T05:40:53

the probability is $\frac{1}{12}$ $1/12$

You will get 36 possible cases with two sided dices :

(1,1), (1,2),(1,3),...,(64),(6,5),(6,6)

but only these ones will give you a sum less than equal to 10:

(6,4),(4,6),(5,5)

Then the probability is:

$p = \frac{3}{36} = \frac{1}{12}$ $p=3/36=1/12$

Answer 2 · 2017-02-09T11:53:18

$P (sum \leq 10) = \frac{11}{12}$ $P( "sum" le 10) = 11/12$

There are 36 possible combinations from the two dice which are listed in this table:

The combination where the sum is less than or equal to 10 are coloured, and so

$P (sum \leq 10) = \frac{36 - 3}{36} = \frac{33}{36} = \frac{11}{12}$ $P( "sum" le 10) = (36-3)/36 = 33/36 = 11/12$