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A squirrel sitting on the ground starts to run with an acceleration of $5.1$ $m$ $/$ $s^2$ . How fast is the squirrel going after $.25$ seconds?

1 Answer

Nov 26, 2015

$1.27"m/s"$

Explanation:

Use $v=u+at$

Since $u$ , the initial velocity, is zero we can write:

$v=0+at$

$:.v=0+5.1xx0.25=1.27"m/s"$

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