A square hut with side lengths of 5 m is to be surrounded by a veranda of width x metres. Find the width of the veranda if its area is to be 24 m^2?

2 Answers
Jul 9, 2017

WIdth of veranda=1m

Explanation:

Total area of hut + veranda
=25+24=49m^2

So veranda sides=7m

7m-5m=2m

So veranda width=1m

~~~~~~~~~~~~~~~~~~~~~~~

Check:

Veranda on 2 sides=1m by 7m=7m^2*2=14m^2

Veranda on 2 sides=1m by 5m=5m^2*2=10m^2

14m^2+10m^2=24m^2=area of veranda

Jul 10, 2017

"width " =1m

Explanation:

"the length of the hut and veranda " =5+2x

rArr" the width of the hut and veranda " =5+2x

rArr(5+2x)^2-25=24

"distribute and equate to zero"

rArr25+20x+4x^2-25-24=0

rArr4x^2+20x-24=0larr" common factor of 4"

rArr4(x^2+5x-6)=0

rArr(x+6)(x-1)=0

rArrx=-6" or " x=1

x>0rArrx=1

color(blue)"As a check"

5+2x=5+2=7

"area of veranda "=7^2-5^2=49-25=24larr" True"

rArr"width of veranda " =1" m"