A solution contains 72.0 g of #HCl# and 468 g of #C_6H_6#. What is the mole fraction of benzene?

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Answer 1 · 2016-09-15T06:07:35

The mole fraction of benzene is 0.752.

The mole fraction of a substance in a solution is equal to the moles of the substance divided by the total moles of all substances in the solution.

#"Mole fraction"##=##"mol X"/"mol X+mol Y"#

The mass of each compound needs to be converted to moles by dividing the mass by its molar mass.

First determine the molar mass of both compounds.

Molar Mass HCl:

#(1xx1.008 "g/mol")+(1xx35.45 "g/mol")="36.458 g/mol"#

Molar Mass #"C"_6"H"_6"#:

#(6xx12.011"g/mol")+(6xx1.008"g/mol")="78.114 g/mol"#

Next determine the moles present for each compound by dividing the mass given in the question by its molar mass.

Moles HCl:

#"72.0 g HCl"xx"1 mol HCl"/"36.458 g HCl"="1.974 mol HCl"#

Moles #"C"_6"H"_6":#

#"468 g C"_6"H"_6xx("1 mol C"_6"H"_6)/("78.114 g C"_6"H"_6)="5.991 mol C"_6"H"_6"#

Determine the Mole Fraction of Benzene

#"C"_6"H"_6"##rArr##"5.991"/"5.991+1.974"="0.752"#