A solid disk with a radius of $9 m$ and mass of $4 kg$ is rotating on a frictionless surface. If $360 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $15 Hz$ ?

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Answer 1 · 2017-05-01T05:08:01

The torque is $=3.82Nm$

Mass of disc $=4kg$

Radius of disc $=9m$

The power is related to the torque by the equation

$P=tau *omega$

$P=360W$

Frequency of rotation is $f=15Hz$

$omega=f*2pi$

angular velocity, $omega=(15*2pi )rads^-1$

torque, $tau=P/omega$

$=360/(30pi)=3.82Nm$

A solid disk with a radius of 9 m9 m and mass of 4 kg4 kg is rotating on a frictionless surface. If 360 W360 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 15 Hz15 Hz?