A solid disk with a radius of $8 m$ and mass of $8 kg$ is rotating on a frictionless surface. If $360 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $6 Hz$ ?

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Answer 1 · 2017-02-09T19:46:12

$tau=(360)/(12pi)~~9.55N*m$

We are told we have a rotating spinning coin.

![http://www.mariowiki.com/coin]( useruploads.socratic.org )

Step 1. Gather the information that you know and need

Step 2. Determine the formula using the above givens

Step 3. Plug your answer into the formula for torque

$tau=(360)/(12pi)~~9.55N*m$

A solid disk with a radius of 8 m8 m and mass of 8 kg8 kg is rotating on a frictionless surface. If 360 W360 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 6 Hz6 Hz?