A solid disk with a radius of $8 m$ and mass of $6 kg$ is rotating on a frictionless surface. If $960 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $25 Hz$ ?

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Answer 1 · 2017-11-11T01:45:56

$"6.1 Nm"$ of Torque is applied on disc.

$"Power = Torque × Angular Velocity"$

$"Torque" = "Power" / "Angular Velocity" = ("960 Watt") / ("2 π × 25 Hz") = "6.1 Nm"$

A solid disk with a radius of 8 m8 m and mass of 6 kg6 kg is rotating on a frictionless surface. If 960 W960 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 25 Hz25 Hz?