A solid disk with a radius of $8 m$ $8 m$ and mass of $5 k g$ $5 kg$ is rotating on a frictionless surface. If $640 W$ $640 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $16 H z$ $16 Hz$ ?

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Answer 1 · 2017-03-01T10:01:51

The torque is $= 6.37 N m$ $=6.37Nm$

The power and the torque are related by the following equation

$P = τ ω$ $P=tau omega$

Power $= 3 W$ $=3W$

The angular velocity $= 16 \cdot 2 π = 32 π r a d s^{- 1}$ $=16*2pi=32pirads^-1$

The torque is

$τ = \frac{P}{ω} = \frac{640}{32 π} = 6.37 N m$ $tau=P/omega=640/(32pi)=6.37Nm$

A solid disk with a radius of 8m8 m and mass of 5kg5 kg is rotating on a frictionless surface. If 640W640 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 16Hz16 Hz?