A solid disk with a radius of $7 m$ and mass of $12 kg$ is rotating on a frictionless surface. If $15 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $15 Hz$ ?

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Answer 1 · 2017-04-11T11:04:35

The torque is $=0.64Nm$

Mass of disc $=12kg$

Radius of disc $=7m$

The power is related to the torque by the equation

$P=tau *omega$

$P=15W$

Frequency of rotation is $f=15Hz$

$omega=f*2pi$

angular velocity, $omega=15*2pi rads^-1$

torque, $tau=P/omega$

$=15/(30pi)=0.64Nm$

A solid disk with a radius of 7 m7 m and mass of 12 kg12 kg is rotating on a frictionless surface. If 15 W15 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 15 Hz15 Hz?