A solid disk with a radius of $6 m$ and mass of $2 kg$ is rotating on a frictionless surface. If $120 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $9 Hz$ ?

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Answer 1 · 2017-05-05T06:15:19

The torque is $=2.12Nm$

Mass of disc $=2kg$

Radius of disc $=6m$

The power is related to the torque by the equation

$P=tau *omega$

$P=120W$

Frequency of rotation is $f=9Hz$

$omega=f*2pi$

angular velocity, $omega=9*2pi rads^-1$

torque, $tau=P/omega$

$=120/(18pi)=2.12Nm$

A solid disk with a radius of 6 m6 m and mass of 2 kg2 kg is rotating on a frictionless surface. If 120 W120 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 9 Hz9 Hz?