A solid disk with a radius of $5 m$ $5 m$ and mass of $4 k g$ $4 kg$ is rotating on a frictionless surface. If $3 W$ $3 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $4 H z$ $4 Hz$ ?

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A solid disk with a radius of $5 m$ $5 m$ and mass of $4 k g$ $4 kg$ is rotating on a frictionless surface. If $3 W$ $3 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $4 H z$ $4 Hz$ ?

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Answer 1 · 2017-11-11T01:43:13

$0.12 Nm$ $"0.12 Nm"$ of Torque was applied on the disc.

Explanation:

$Power = Torque \times Angular Velocity$ $"Power = Torque × Angular Velocity"$

$Torque = \frac{Power}{Angular Velocity} = \frac{3 Watt}{2 π \times 4 Hz} = 0.12 Nm$ $"Torque" = "Power" / "Angular Velocity" = ("3 Watt") / ("2 π × 4 Hz") = "0.12 Nm"$

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A solid disk with a radius of $5 m$ $5 m$ and mass of $4 k g$ $4 kg$ is rotating on a frictionless surface. If $3 W$ $3 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $4 H z$ $4 Hz$ ?

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Explanation:

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Humanities

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A solid disk with a radius of 5m5 m and mass of 4kg4 kg is rotating on a frictionless surface. If 3W3 W of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at 4Hz4 Hz?

1 Answer

Explanation:

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A solid disk with a radius of $5 m$ $5 m$ and mass of $4 k g$ $4 kg$ is rotating on a frictionless surface. If $3 W$ $3 W$ of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at $4 H z$ $4 Hz$ ?